How many kilowatt-hours of electricity are used to produce 4.50 kg of magnesium in the electrolysis of molten mgcl2 with an applied emf of 5.00 v?

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23-07-2017
Chemistry

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How many kilowatt-hours of electricity are used to produce 4.50 kg of magnesium in the electrolysis of molten mgcl2 with an applied emf of 5.00 v?

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Erythrosin17 Erythrosin17 · Answer 1 · 2017-08-04T03:08:15+02:00

First, we need to determine the half reaction of magnesium. It would be expressed as:

Mg2+ + 2e- = Mg

Given the mass of magnesium metal that is produced, we calculate the total charge of the electrolysis by the relations we can get from the half reaction. We do as follows:

4.50 kg Mg ( 1000 g / 1 kg ) ( 1 mol / 24.305 g ) ( 2 mol e- / 1 mol Mg ) ( 96500 C / 1 mol e- ) = 35733388.2 C

We are given the applied EMF in units of V. This value is equal to J/C. So, 5 V is equal to 5 J/C.

35733388.2 C (5 J/C) = 178666941 J
178666941 J ( 1 kW-h / 3.6x10^6 J ) = 49.63 kW-h

shristiparmar1221 shristiparmar1221 · Answer 2 · 2022-07-01T17:16:48+02:00

The kilowatt-hours of electricity are used to produce 4.50 kg of magnesium in the electrolysis of molten MgCl₂ with an applied emf of 5.00 v is 49.63 kW-h. It can be find by knowing the half reaction of magnesium.

What is Half Reaction ?

A half reaction is either the oxidation or reduction reaction component of a redox reaction.

Let's determine the half reaction of magnesium ;

Mg²⁺ + 2e- => Mg

Given the mass of magnesium metal that is produced, we calculate the total charge of the electrolysis by the relations we can get from the half reaction. We do as follows :

4.50 kg Mg ( 1000 g / 1 kg ) ( 1 mol / 24.305 g ) ( 2 mol e- / 1 mol Mg ) (96500 C / 1 mol e-) = 35733388.2 C

We are given the applied EMF in units of V. This value is equal to J/C. So, 5 V is equal to 5 J/C.

35733388.2 C (5 J/C) = 178666941 J

178666941 J ( 1 kW-h / 3.6x10^6 J ) = 49.63 kW-h

Hence, The kilowatt-hours of electricity are used to produce 4.50 kg of magnesium in the electrolysis of molten MgCl₂ with an applied emf of 5.00 v is 49.63 kW-h.

Learn more about redox reaction here ;

https://brainly.com/question/13978139

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