An electric device delivers a current of 5 a to a device. how many electrons flow through this device in 5 s? (e = 1.60 × 10-19 c)

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W0lf93
2*10^20 electrons Electron flow rate is given by I/e, where I is the current in amps and e is the electric charge constant, in coulombs. This will have units of electrons per second, so we must multiply by the time, t, in seconds. So the full equation is: N = (I*t)/e Plugging in: N = (5a * 5s)/(1.6*10^-19 c) N = 1.5625*10^20 electrons But since we only have 1 significant figure to work with, we state our final value as N = 2*10^20 electrons

1.5625.10²⁰ electrons are flowing through this device in 5 s

Further explanation

Electric current is the amount of electric charge that flows each unit of time

Electric current can also be a ratio between voltage and resistance

Electric current occurs due to the movement of electrons due to the difference in potential or voltage (from high potential to low potential) between two points

Electrons will flow through the conducting wire that functions as a conductor

The electric current itself can be divided into direct current (DC) or alternating current (AC)

Can be formulated:

[tex]{\displaystyle I = {\frac {Q} {t}},}[/tex]

Where

I is the electric current, Ampere (A)

Q is the electric charge, coulomb (C)

t is time, seconds (s)

An electric device delivers a current of 5 A within 5 s, so the charge is:

Q = I x t

Q = 5 x 5

Q = 25 C

Because 1 electron (e) has a charge of 1.60 × 10⁻¹⁹ C, so the total number of electrons flowing:

= 25 C: 1.60 × 10⁻¹⁹ C

= 15.625.10¹⁹

= 1.5625.10²⁰ e

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Keywords: electric current, electric charge, electrons, coulombs, amperes, seconds

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