Answer:
9
Explanation:
Hello,
In this case, since the third shell of electrons has the following 3 subshells:
[tex]3s, 3p \ and \ 3d[/tex]
- The [tex]s[/tex] subsehll has one orbital for one pair of electrons: [tex]s^1 \ and \ s^2[/tex].
- The [tex]p[/tex] subsehll has three orbitals for three pairs of electrons: [tex]p^1, \ p^2,\ p^3, \ p^4,\ p^5\ and \ p^6\[/tex].
- The [tex]d[/tex] subsehll has five orbital for five pairs of electrons [tex]d^1, \ d^2,\ d^3, \ d^4,\ d^5,\ d^6,\ d^7,\ d^8,\ d^9\ and \ d^{10}\[/tex].
Therefore, the total number of orbitals when n=3 is:
[tex]1+3+5=9[/tex]
Best regards.
