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A 24.0N picture hangs from a nail in the wall. The diameter of the nail is 2.00 mm. The shear stress on the nail is

Respuesta :

Weight tending to shear the pin is
W = 24.0 N
The shear area of the pin is
A = (π/4)*(2.0 x 10⁻³ m)² = 3.1416 x 10⁻⁶ m².

The shear stress is
τ = (24.0 N)/(3.1416 x 10⁻⁶ m²)
  = 7.64 x 10⁶ Pa
  = 7.64 MPa

Answer: 7.64 Mpa

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