Respuesta :

[tex]\bf tan(\theta)=\cfrac{y}{x}\\\\ -------------------------------\\\\ \begin{array}{clclll} (\frac{3}{5}&\ ,\ &\frac{4}{5})\\ \uparrow &&\uparrow \\ x&&y \end{array}\qquad tan(\theta )=\cfrac{\frac{4}{5}}{\frac{3}{5}}\implies tan(\theta )=\cfrac{4}{5}\cdot \cfrac{5}{3}\implies tan(\theta )=\cfrac{4}{3}[/tex]