Respuesta :

f(x) = 2x^2 + 5sqrt (x - 2)....when x = 6
f(6) = 2(6^2) + 5 sqrt (6 - 2)
f(6) = 2(36) + 5 sqrt 4
f(6) = 72 + 5 * 2
f(6) = 72 + 10
f(6) = 82

The value of f(6) in the function [tex]f(x)=2x^2 + 5\sqrt{x-2}[/tex]  is 82

How to determine the function value?

The function is given as:

[tex]f(x)=2x^2 + 5\sqrt{x-2}[/tex]

Substitute 6 for x

[tex]f(6)=2 * 6^2 + 5\sqrt{6-2}[/tex]

Evaluate the difference

[tex]f(6)=2 * 6^2 + 5\sqrt{4}[/tex]

Evaluate the exponents

f(6)=2 * 36 + 5 * 2

Evaluate the sum of products

f(6) = 82

Hence, the value of f(6) in the function [tex]f(x)=2x^2 + 5\sqrt{x-2}[/tex]  is 82

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