Answer: Where:
θ = confidence value
n = number of observations
μ = mean
Θ = standard deviation
... then your interval will be:
μ - θΘ/√n ≤ X ≤ μ - θΘ/√n
For some reason they want you to calculate the standard error, which is the Θ/√n section, and I mentioned the 1.96 value, so the above equation simplifies to: μ - 1.96SE ≤ X ≤ μ - 1.96SE