Respuesta :

Willchemistry
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Molar mass carbon dioxide:

CO2 = 44.01 g/mol

1) number of moles :

1 mole CO2 ------------- 44.01 g
(moles CO2) ------------ 243.6 g

moles CO2 = 243.6 * 1 / 44.01

moles CO2 = 243.6 / 44.01

=> 5.535 moles of CO2

Therefore:

1 mole -------------------- 6.02x10²³ molecules
5.535 moles ------------ ( molecules CO2)

molecules CO2 = 5.535 * ( 6.02x10²³) / 1

=> 3.33x10²⁴ molecules of CO2

The number of molecules of carbon dioxide present in 243.6 g of carbon dioxide is 3.33 × 10²⁴ molecules

From the question,

We are to determine the number of molecules of carbon dioxide that are in 243.6g of carbon dioxide

First, we will determine the number of moles of carbon dioxide present

Using the formula,

[tex]Number\ of\ moles\ = \frac{Mass}{Molar\ mass}[/tex]

Molar mass of carbon dioxide = 44.01 g/mol

Number of moles of carbon dioxide = [tex]\frac{243.6}{44.01}[/tex]

Number of moles of carbon dioxide = 5.5351 moles

Now, for the number of molecules,

Using the formula,

Number of molecules = Number of moles × Avogadro's constant

Number of molecules = 5.5351 × 6.022 × 10²³

Number of molecules of carbon dioxide = 3.33 × 10²⁴ molecules

Hence, the number of molecules of carbon dioxide present in 243.6 g of carbon dioxide is 3.33 × 10²⁴ molecules

Learn more on calculating number of molecules here: https://brainly.com/question/14464650

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