Answer:
The required inequality that shows the maximum number of packages is [tex]n\leq 67[/tex].
Step-by-step explanation:
Consider the provided information.
Each package weighs 3 pounds and Jacob weighs 99 pounds.
let n is the maximum number of package that Jacob can carry with himself in the elevator.
Thus, the total weight of Jacob while having n packages on the elevator is:
[tex]3n+99[/tex]
The elevator can carry a maximum of 300 pounds at a time, therefore.
[tex]3n+99\leq 300[/tex]
Now, subtract 99 from both sides and divide the obtained inequality with 3.
[tex]3n+99-99\leq 300-99[/tex]
[tex]3n\leq 201[/tex]
[tex]\frac{3n}{3}\leq \frac{201}{3}[/tex]
[tex]n\leq 67[/tex]
Thus, the Jacob can carry maximum 67 packages.
Hence, the required inequality that shows the maximum number of packages is [tex]n\leq 67[/tex].
Answer:
It would be n ≤ 67
Step-by-step explanation:
Hope this helps! I took the test btw and got it correct! :)
