Answer:
28 phones
Step-by-step explanation:
Define the variables:
- Let x be the price of one printer.
- Let y be the price of one phone.
- Let z be the price of one computer.
Given that we can buy 5 printers for the price of 2 phones and one computer, this can be represented by the equation:
[tex]5x = 2y + z[/tex]
Given that the price of one computer is 4 times higher than the price of a printer, this can be represented by the equation:
[tex]z = 4x[/tex]
Substitute the second equation (z = 4x) into the first equation (5x = 2y + z) and solve for x:
[tex]\begin{aligned}5x &= 2y + 4x\\5x-4x&=2y+4x-4x\\x&=2y\end{aligned}[/tex]
Therefore, the price of one printer is equal to the price of 2 phones.
The expression for the price of 3 computers and 2 printers is:
[tex]3z + 2x[/tex]
Substitute z = 4x into 3z + 2x:
[tex]\begin{aligned}3z + 2x &= 3(4x) + 2x\\&=12x+2x\\&=14x\end{aligned}[/tex]
Now, substitute x = 2y:
[tex]\begin{aligned}&=14(2y)\\&=28y\end{aligned}[/tex]
Therefore, 28 phones can be bought for the price of 3 computers and 2 printers.
