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Carlos performed a transformation on trapezoid EFGH to
create E'F'G'H', as shown in the figure below (pic)

What transformation did Carlos perform to create E'F'G'H'?

1 Rotation of 270° clockwise about the origin

2 Reflection across the x-axis

3 Rotation of 90° clockwise about the origin

4 Reflection across the line of symmetry of the figure

Carlos performed a transformation on trapezoid EFGH to create EFGH as shown in the figure below pic What transformation did Carlos perform to create EFGH 1 Rota class=

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sqdancefan

Answer:

  3 Rotation of 90° clockwise about the origin

Step-by-step explanation:

You want to know the transformation that maps EFGH to E'F'G'H'.

Quadrant

The original figure EFGH is located in the 3rd quadrant. Its image figure E'F'G'H' is located in the 2nd quadrant. It can get there either by reflection across the x-axis, or by rotation 90° CW.

Orientation

The line segment EF points to the right. The line segment E'F' points down. This means the figure has been rotated, not reflected. (Reflection across the x-axis will leave horizontal segments parallel.)

The transformation is rotation 90° CW, choice 3.

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