Find the points of intersection for these two figures:

((x-255)/250)^2 + (y/108.9)^2 = 1

((x-1.5)/93)^2 + (y/93)^2 = 1


According to my teacher you cannot set them equal to each other and also work has to be shown :p

Respuesta :

To find the points of intersection of the two ellipses, we can solve the system of equations:

((x-255)/250)^2 + (y/108.9)^2 = 1

((x-1.5)/93)^2 + (y/93)^2 = 1

To do this, we can solve one of the equations for y and substitute the expression into the other equation.

First, let's solve the second equation for y:

((x-1.5)/93)^2 + (y/93)^2 = 1

(y/93)^2 = 1 - ((x-1.5)/93)^2

y/93 = ±sqrt(1 - ((x-1.5)/93)^2)

y = ±93*sqrt(1 - ((x-1.5)/93)^2)

Now we can substitute this expression for y into the first equation and solve for x:

((x-255)/250)^2 + (±93*sqrt(1 - ((x-1.5)/93)^2)/108.9)^2 = 1