Answer:
the specific heat capacity of the solid is approximately 2.52 × 10^2 J/kg K.
Explanation: To find the specific heat capacity of the solid, we can use the equation:
Q = mcΔT
where Q is the heat absorbed or released, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the solid of mass 200 g is heated to a temperature of 80°C. We also know that it melts 40 grams of ice.
To find the heat absorbed by the solid, we can use the equation:
Q = mL
where L is the specific latent heat of ice.
In this case, the heat absorbed by the solid is equal to the heat released by the ice, since they are in thermal equilibrium. Therefore, we can write:
mcΔT = mL
Rearranging the equation, we get:
c = (mL) / (mΔT)
Substituting the given values, we have:
c = (40 g * 3.36×10^5 J/kg K) / (200 g * 80°C)
Simplifying, we get:
c = (40 * 3.36×10^5) / (200 * 80)
c ≈ 2.52 × 10^2 J/kg K
