a plastic wading pool has a mass of 5 kg. when filled with water, the water in it has a mass of 400kg. how much force is required to set the filled pool on motion if the coefficient of maximum static friction is 0.22?​

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Answer:

To calculate the force required to set the filled pool in motion, we need to consider the maximum static friction between the pool and the surface it rests on. The maximum static friction force can be found using the equation:

Friction force = coefficient of static friction * normal force

The normal force is equal to the weight of the filled pool, which is the mass of the water inside the pool multiplied by the acceleration due to gravity (9.8 m/s^2).

Given:

Mass of the pool (m) = 5 kg

Mass of the water (m_water) = 400 kg

Coefficient of maximum static friction (μ) = 0.22

Acceleration due to gravity (g) = 9.8 m/s^2

Calculating the weight of the filled pool:

Weight = m_water * g

Weight = 400 kg * 9.8 m/s^2

Weight = 3920 N

Calculating the friction force:

Friction force = μ * normal force

Friction force = 0.22 * 3920 N

Friction force ≈ 862.4 N

Therefore, approximately 862.4 Newtons of force would be required to set the filled pool in motion.