Find the length of each side of the triangle.

A right angled triangle has hypotenuse two centimetres shorter than three times the length of the shortest side. The other side is 7 cm longer than the shortest side.

Find the length of each side of the triangle.

Answer = 5 cm, 12 cm, 13 cm ;
help me with the procedures please !!!

Respuesta :

Answer:

let x be the shortest side

let y be the other side

let z be the hypotenuse

.: y = 7 + x

z = 3x - 2

Answer:

The lengths of the sides of the triangle are 5 cm, 12 cm, and 13 cm, as given in the answer.

Step By Step Explanation:

Let's denote the lengths of the sides of the right-angled triangle as follows:

  • Let a be the length of the shortest side.
  • Let b be the length of the other side (which is 7 cm longer than the shortest side).
  • Let c be the length of the hypotenuse (which is two centimeters shorter than three times the length of the shortest side).

Now, we can set up equations:

The Pythagorean Theorem: In a right-angled triangle, the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b):

[tex]c^2 = a^2+b^2[/tex]

The given relationship between the hypotenuse and the shortest side:  [tex]c = 3a -2[/tex]

The other side is 7 cm longer than the shortest side:

[tex]b= a+7[/tex]

Now, we can use these equations to solve for the lengths of a, b, and c.

Substitute the expression for cc from equation (2) into equation (1):

[tex](3a-2)^2 = a^2 + (a+7)^2[/tex]

Now, solve this equation to find the value of a.

[tex]9a^2 -12a+4 = a^2+a^2+14a+ 49[/tex]

[tex]9a^2-12a+4 = 2a^2+14a+49[/tex]

[tex]7a^2-26a-45=0[/tex]

Now, factor the quadratic equation:

[tex](7a+9)(a-5)=0[/tex]

So,

[tex]a= -\frac{9}{7}[/tex] or [tex]a=5[/tex]

Since the length cannot be negative, we discard the first solution.

So, the length of the shortest side (a) is 5 cm. Now, use this value to find b and c:

[tex]b=a+7= 5+7=12cm[/tex]

[tex]c=3a-2= 3(5)-2=13cm[/tex]