Answer:
Step-by-step explanation:
You want the dimensions of a rectangle with a perimeter of 46 meters and a width that is 2 more than half the length.
Using L and W for the length and width, we are given the relations ...
P = 2(L +W)
46 = 2(L +W) . . . . . equation for perimeter
and
W = 2 +L/2 . . . . . . equation relating length and width
Using the second equation to substitute for W in the first, we have ...
46 = 2(L +(2 +L/2))
46 = 2L +4 +L . . . . . . . . simplify
42 = 3L . . . . . . . . subtract 4
14 = L . . . . . . divide by 3
W = 2 +14/2 = 9 . . . . . find W
The length is 14 meters; the width is 9 meters.