Respuesta :
The answer is 5.33 x 10^-4
to find the answer follow these steps:
the reaction is first order reaction
here k = 6.29 x 10^-4 s^-1
initial concentration = 1.00 x 10^-3
After time t = 1.000 x 10^3 s concentration is = ?
So, - 6.29 x 10^-4 x 1.00 x 10^3 + ln (1.00 x 10^-3) = - 7.54
C = e ^ - 7.54= 5.33 x 10^-4 M
Answer:Concentration of [[tex]CH_3=N\equiv C] after [tex]1.000\times 10^3 s[/tex] is [tex]2.38\times 10^{-8} mol/L[/tex].
Explanation:
Rate constant of the reaction = k = [tex]6.29\times 10^{-4} s^{-1}[/tex]
Initial concentration of [tex][A_o]=1.00\times 10^{-3} mol/L[/tex]
Concentration after time t= [A]
[tex]t = 1.000\times 10^3 s[/tex]
[tex]log[A]=2.303\times \log[A_o]-kt[/tex]
[tex]log[A]=2.303\times \log[1.00\times 10^{-3}]-6.29\times 10^{-4} s^{-1}\times 1.000\times 10^3 s[/tex]
[tex][A]=2.38\times 10^{-8} mol/L[/tex]
Concentration of [[tex]CH_3=N\equiv C] after [tex]1.000\times 10^3 s[/tex] is [tex]2.38\times 10^{-8} mol/L[/tex].
