3x+2y+4z=12
X+y+2z=6
(X=0,y=4,z=1)
Determine if the given 2 lines intersect at the given point. Explain your reasoning.
-2x-4y+z=8
4x+2y=-5
(x=-2,y=0,z=3) same as up above
Substitute the given points into each equation and if the answer is as intended for both equation, then it means the given points are the intersection point
Given points x = 0, y = 4, and z = 1 Equation 1: 3x + 2y + 4z = 3(0) + 2(4) + 4(1) = 0 + 8 + 4 = 12 Equation 2: x + y + 2z = 0 + 4 + 2(1) = 6
Both equation 1 and equation 2 give the intended answer; 12 and 6 respectively, hence the given point is the intersection point ---------------------------------------------------------------------------------------------------------------
