To solve this problem, we make use of the equations of
motion:
vf^2 = v0^2 – 2 g h
vf = v0 – g t
h = v0 t – 0.5 g t^2
A. Finding for max height:
Max height occurs when vf = 0, therefore:
0^2 = 25^2 – 2 (9.8) h
h = 31.89 m
B. Finding for t:
t = t(up) + t(down)
vf = v0 – g t(up)
0 = 25 – 9.8 t(up)
t(up) = 2.55 s
h = v0 t(down) – 0.5 g t(down)^2
31.89 = 0.5 (9.8) t(down)^2
t(down)^2 = 6.51
t(down) = 2.55 s
so,
t = 5.1 s
