The integers are 54, 55, 56 and 57
Let the integers be n, n + 1, n + 2 and n + 3.
Since the sum of the integers equals 222, we have that
n + n + 1 + n + 2 + n + 3 = 222
Collecting like terms, we have
n + n + n + n + 1 + 2 + 3 = 222
Simplifying, we have
4n + 6 = 222
Subtracting 6 from both sides, we have
4n + 6 - 6 = 222 - 6
4n = 216
Dividing both sides by 4, we have
n = 216/4
n = 54
Since n = 54, the first integers is 54
The second integer is n + 1 = 54 + 1 = 55,
The third integer is n + 2 = 54 + 2 = 56 and
The fourth integer is n + 3 = 54 + 3 = 57
So, the integers are 54, 55, 56 and 57
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