Every fourth visitor to a museum gets a free bumper sticker.Every tenth visitor to that museum gets a free key chain.Which ordered visitor will be the first one to get both the bumper sticker and the chain?

Respuesta :

You have to use least common multiple so that's going to be
4-8-12-16-20
10-20
The 20th person gets both first

Answer:

The [tex]20^{th}[/tex] visitor will get both a bumper sticker and free key chain.

Step-by-step explanation:

We are given the following information in the question:

Every [tex]4^{th}[/tex] visitor gets a bumper ticket in the museum.

Also, every [tex]10^{th}[/tex] visitor gets a free key chain.

We have to find a visitor that will get both the bumper ticket and the free key chain.

This can be done by finding Lowest common multiple(LCM) of 4 and 10.

Lowest common multiple of 4 and 10 is smallest possible number that  is divisible by both 4 and 10.

We can do this with the help of prime factorization.

[tex]4 = 2\times 2[/tex]

[tex]10 = 2\times 5[/tex]

[tex]\bold{LCM} = 2\times 2\times 5 = 20[/tex]

Hence, the [tex]20^{th}[/tex] visitor will get both a bumper sticker and free key chain.