a. This velocity in kilometers per hour is 1674 km/h
b. This velocity in kilometers per day is 40176 km/day
Acceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem !
If earth rotates with a velocity of about 465 m/s at the equator , then it means that earth covers 465 metres in 1 second.
465 metres = 465 / 1000 kilometres = 0.465 kilometres
1 hour = 3600 seconds → 1 second = 1 / 3600 hour
1 day = 24 hours = 86400 seconds → 1 second = 1 / 86400 hour
The velocity in kilometres per hour can be calculated as following:
[tex]velocity = 465 ~ m \div 1 ~ s[/tex]
[tex]velocity = 0.465 ~ km \div \frac{1}{3600} ~ h[/tex]
[tex]velocity = 0.465 \div \frac{1}{3600} ~ km/h[/tex]
[tex]velocity = 0.465 \times 3600 ~ km/h[/tex]
[tex]\boxed {velocity = 1674 ~ km/h}[/tex]
The velocity in kilometres per day can be calculated as following:
[tex]velocity = 465 ~ m \div 1 ~ s[/tex]
[tex]velocity = 0.465 ~ km \div \frac{1}{86400} ~ day[/tex]
[tex]velocity = 0.465 \div \frac{1}{86400} ~ km/day[/tex]
[tex]velocity = 0.465 \times 86400 ~ km/day[/tex]
[tex]\boxed {velocity = 40176 ~ km/day}[/tex]
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate
