HURRY PLEASE :)!!

The triangles are similar. The area of the larger triangle is 206 ft^2. Find the area of the smaller triangle to the nearest whole number.

HURRY PLEASE The triangles are similar The area of the larger triangle is 206 ft2 Find the area of the smaller triangle to the nearest whole number class=

Respuesta :

Since the triangles are similar, the ratio of the sides of larger triangle to the smaller triangle is a constant.

That constant = [tex] \frac{15}{9} = \frac{5}{3} [/tex]

Since the sides are in that constant proportion, the area of the triangles will also be in proportion.

(Area of larger triangle) over (Area of smaller triangle) = [tex]\frac{5}{3} [/tex]

[tex] \frac{206}{x} = \frac{5}{3} [/tex]

[tex]x = 206 * \frac{3}{5} = \frac{618}{5} [/tex] = 123.6 ≈ 124

Hence, to the nearest whole number the area of smaller triangle is 124 ft².

Answer:

Area of the smaller triangle 74  ft².

Step-by-step explanation:

Given  : The triangles are similar. The area of the larger triangle is 206 ft^2.

To find : Find the area of the smaller triangle to the nearest whole number.

Solution : We have given that triangles are similar and area of the larger triangle is 206 ft^2.

By the similar triangles property : [tex]\frac{Area\ of\ triangle 1}{Area\ of\ triangle\ 2} = \frac{(side\ of\ triangle\ 1)^{2}}{(side\ of\ triangle\ 2)^{2} }[/tex].

Then Side of triangle 1 = 15 ft .

Side of triangle 2 = 9 ft.

Area of triangle 1 = 206 ft².

Let area of triangle 2 = x.

Then ,

Ratio of sides = [tex]\frac{15}{9}[/tex] =  [tex]\frac{5}{3}[/tex]

[tex]\frac{206}{x} = \frac{(5)^{2}}{(3)^{2} }[/tex].

[tex]\frac{206}{x} = \frac{(25}{9}[/tex].

On cross multiplication :

206 * 9 = 25  *x

1854 = 25 * x .

On dividing by 25

x = 74.16 ft².

Therefore, Area of the smaller triangle 74  ft².