Respuesta :

Answer: 250 ml

Explanation:

According to the dilution law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock [tex]HNO_3[/tex] solution = 16 M

[tex]V_1[/tex] = volume of stock [tex]HNO_3[/tex] solution = ?

[tex]M_2[/tex] = molarity of diluted [tex]HNO_3[/tex] solution = 2.00 M

[tex]V_2[/tex] = volume of diluted [tex]HNO_3[/tex] solution = 2.00 L

[tex]16\times V_1=2\times 2[/tex]

[tex]V_1=0.25L=250ml[/tex]      (Conversion factor: 1L=1000ml)

Therefore, 250 ml of concentrated nitric acid should be diluted with water.

Taking into account the definition of dilution, 250 mL of concentrated nitric acid 16 M should be diluted with water in order to make 2.00 L of 2.00 M solution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

In this case, you know:

  • Ci: 16 M
  • Vi: ?
  • Cf: 2 M
  • Vf: 2 L

Replacing:

16 M× Vi= 2 M× 2 L

Solving:

[tex]Vi=\frac{2 Lx 2 M}{16 M}[/tex]

Vi= 0.25 L= 250 mL (being 1 L= 1000 mL)

In summary, 250 mL of concentrated nitric acid 16 M should be diluted with water in order to make 2.00 L of 2.00 M solution.

Learn more about dilution:

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