Respuesta :
x=2y^2 -8
or
2y^2= x+8
y^2 = (x+8)/2
[tex]y = \sqrt{ \frac{x+8}{2} } [/tex]
or
2y^2= x+8
y^2 = (x+8)/2
[tex]y = \sqrt{ \frac{x+8}{2} } [/tex]
we have
[tex]y=2x^{2} -8[/tex]
Step [tex]1[/tex]
Exchanges the variable x for y and the variable y for x
[tex]x=2y^{2} -8[/tex]
Step [tex]2[/tex]
Clear the variable y
[tex]2y^{2}=x+8[/tex]
[tex]y^{2}=\frac{x+8}{2} \\ \\y=(+/-)\sqrt{\frac{x+8}{2}}[/tex]
so
the inverse is equal to-------> [tex]y=(+/-)\sqrt{\frac{x+8}{2}}[/tex]
therefore
the answer is
[tex]y=(+/-)\sqrt{\frac{x+8}{2}}[/tex]