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The diagonals of quadrilateral ABCD intersect at point E, AE=5x-10,EC=2x+5, and BE= y/3.. If ABCD is a square, find the value of y. A. 5 B. 15 C. 30 D. 45

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Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

As we are given, quadrilateral ABCD is square.

Means its diagonals will intersect each other at their mid point.

So,  [tex]AE =EC[/tex]

[tex]5x-10=2x+5[/tex]

[tex]5x-2x= 5+10[/tex]

[tex]3x = 15[/tex]

[tex]x = 5[/tex]

It means AE = [tex]5x-10 = 5(5)-10 = 25-10=15[/tex]

[tex]AE = BE[/tex]

So,

[tex]\frac{y}{3} = 15[/tex]

[tex]y = 45[/tex]

hence answer is 45.   :   Answer

Hope it will help :)

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