m(x)=x+5/x+1, n(x)=x-3, what is m(n(x))?

I know the answer is 11/x-4 but I don't know where the 11 came from.
I need it worked out step by step.

Respuesta :

subsitute n(x) for x in M(x)

[tex]M(n(x))=\frac{n(x)+5}{n(x)+1}=[/tex]
[tex]M(x-3)=\frac{(x-3)+5}{(x-3)+1}=[/tex]
[tex]M(x-3)=\frac{x-3+5}{x-3+1}=[/tex]
[tex]M(x-3)=\frac{x+25}{x-2}=[/tex]

 I have no idea where you got [tex]\frac{11}{x-4}[/tex]