Respuesta :

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -5}}\quad ,&{{ 5}})\quad % (c,d) &({{ 2}}\quad ,&{{ 6}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ d=\sqrt{[2-(-5)]^2+[6-5]^2}\implies d=\sqrt{(2+5)^2+(6-5)^2} \\\\\\ d=\sqrt{7^2+1^2}\implies d=\sqrt{50}[/tex]