The question can be read as how many [tex]3 \frac{7}{8} [/tex] can be made out of [tex]131 \frac{3}{4} [/tex]
[tex]131 \frac{3}{4} [/tex]÷[tex]3 \frac{7}{8} [/tex] ⇒ We need to change each mixed number into an improper fraction
[tex]131 \frac{3}{4}= \frac{[131*4]+3}{4}= \frac{527}{4} [/tex]
[tex]3 \frac{7}{8}= \frac{[3*8]+7}{8} = \frac{31}{8} [/tex]
[tex] \frac{527}{4} [/tex]÷[tex] \frac{31}{8} [/tex]
[tex] \frac{527}{4} [/tex]×[tex] \frac{8}{31} [/tex]
[tex] \frac{527*8}{4*31}= \frac{4216}{248} =17[/tex]
Answer: 17 uniform
