Answer:
[tex] \sf \overline{EF} = \boxed{\quad 2 \quad } [/tex]
Step-by-step explanation:
When a line segment is dilated by a scale factor, the lengths of the original and dilated segments are related by that scale factor.
In this case, if the length of the dilated segment E'F' is 8 and the scale factor is 4, the original length [tex]\sf \overline{EF} [/tex] can be found by dividing the length of the dilated segment by the scale factor:
[tex]\Large\boxed{\boxed{\sf \overline{EF} = \dfrac{\sf E'F'}{\textsf{Scale Factor}} }}[/tex]
[tex] \sf \overline{EF} = \dfrac{8}{4} [/tex]
[tex] \sf \overline{EF} = 2 [/tex]
Therefore, the measure of [tex] \sf \overline{EF}[/tex] is 2 units.
