The length of a rectangular garden is six less than twice its width. If the area of the garden is 80 square feet. Find the dimensions.

Respuesta :

Answer: 10 feet by 8 feet

Step-by-step explanation:

The area of a rectangle is given by the formula:

A = L·W, where:

  • A is the area
  • L is the length
  • W is the width

In this case:

  • A = 80 ft²
  • L = 2W - 6 (six less than twice its width)

Let's plug these into the formula:

A = L·W

80 = (2W - 6)·(W)

Use the distributive property to multiply the two terms together on the right side:

80 = 2W² - 6W

Now, solve the equation for W. We can solve this quadratic equation by subtracting 80 from both sides to set the equation equal to 0:

2W² - 6W - 80 = 0

Factor the quadratic equation:

2(W² - 3W - 40) = 0

2(W - 8)(W + 5) = 0

Now, we have 2 possible solutions for W:

W = 8 and W = -5. Since width cannot be negative, W = 8 feet.

Now, we can find the length (L) using the expression above:

L = 2W - 6

L = 2(8) - 6

L = 10 feet

The dimensions of the rectangular garden are 10 feet by 8 feet.

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