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A 75.5-kg hiker starts at an elevation of 1300 m and climbs to the top of a peak 2620 m high. What is the minimum work required of the hiker?

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audreyn06

Answer: 977664.6 J

Explanation:

The work in this case can be found by calculating the change in gravitational potential energy, which is given as:

ΔU = mgΔh, where:

  • ΔU is the change in gravitational potential energy
  • m is the mass
  • g is the acceleration due to gravity
  • Δh is the change in height

In this case:

  • We are solving for ΔU, which is also the work required of the hiker
  • m = 75.5 kg
  • g = 9.81 m/s²
  • Δh = 2620m - 1300m = 1320 m

Let's plug these values into the formula:

ΔU = (75.5)(9.81)(1320)

ΔU = 977664.6 J

The minimum work required of the hiker is 977664.6 J.

Learn more about work here: https://brainly.com/question/31343354

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