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1) The actual weight of a watermelon is 5.2 kg. John measured it and found the weight to be 4.8 kg. Calculate the percent error in John's measurement. ​

Respuesta :

itzamirv2

Given:

- Actual weight = 5.2 kg

- Measured weight = 4.8 kg

To find the percent error, we use the formula:

Percent Error = (|Measured Value - Actual Value| / Actual Value) * 100%

Substitute the given values:

Percent Error = (|4.8 - 5.2| / 5.2) * 100%

Calculate:

Percent Error = (| -0.4 | / 5.2) * 100%

Percent Error = (0.4 / 5.2) * 100%

Percent Error ≈ (0.077 * 100)%

Percent Error ≈ 7.69%

So, the percent error in John's measurement is approximately 7.69%.

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