One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction y of the population who have heard the rumor and the fraction who have not heard the rumor.
Solve the differential equation. (Let
y(0) = y0.)

Respuesta :

The given model for the spread of a rumor can be represented by the following differential equation:

dy/dt = ky(1 - y)

where:

- dy/dt represents the rate of change of the fraction of the population who have heard the rumor over time t.

- k is the constant of proportionality.

- y represents the fraction of the population who have heard the rumor.

To solve this differential equation, we can use separation of variables.

Separate the variables:

dy / (y(1 - y)) = k dt

Integrate both sides:

∫ (1 / (y(1 - y))) dy = ∫ k dt

The integral on the left side can be rewritten using partial fraction decomposition.

1 / (y(1 - y)) = A/y + B/(1 - y)

Multiplying both sides by y(1 - y), we get:

1 = A(1 - y) + By

Let's solve for A and B:

1 = A - Ay + By

1 = A + (B - A)y

This equation must hold for all values of y. Therefore, the coefficients must be equal:

A = 1

B - A = 0 ⟹ B = A = 1

Now, integrate both sides:

∫ (1/y + 1/(1 - y)) dy = ∫ k dt

ln|y| - ln|1 - y| = kt + C

ln|y / (1 - y)| = kt + C

Apply exponentiation:

(y / (1 - y)) = e^(kt + C)

Now, solve for y:

y = (e^(kt + C)) / (1 + e^(kt + C))

Given y(0) = y0:

y0 = (e^C) / (1 + e^C)

Solve for C:

e^C = (y0) / (1 - y0)

Plug back into the solution for y:

y = ((y0 e^(kt)) / (1 - y0 + y0 e^(kt)))

So, the solution to the differential equation is:

y(t) = ((y0 e^(kt)) / (1 - y0 + y0 e^(kt)))