Answer:
A = 9 yd
B = 2 yd
C = 5 yd
D = 5 yd
Surface area: 146 yd²
Step-by-step explanation:
In the rectangular prism
A = length = 9 yd
B = Height = 2 yd
In this case C and D are width, so,
C = width = 5 yd
D = width = 5 yd
Now
To find the surface area of the rectangular prism using the given net, we use the formula for the surface area of a rectangular prism:
[tex] \sf \textsf{Surface Area }= 2(lb + bh + lh) [/tex]
From above, we get
- Length [tex] l = 9 [/tex] yd
- Height [tex] h = 2 [/tex] yd
- Width [tex] w = 5 [/tex] yd
Substitute the given values into the formula:
[tex] S = 2(9 \times 5 + 5 \times 2 + 9 \times 2) [/tex]
[tex] S = 2(45 + 10 + 18) [/tex]
[tex] S = 2(73) [/tex]
[tex] S = 146 [/tex]
So, the surface area of the prism is 146 yd².
