Respuesta :
Answer :
- Ayi = 16 y/o
- Kwame = 9 y/o
Explanation :
Let the age of kwame be x and that of Ayi be x + 7
ATQ,
- x + x + 7 = 25
- 2x + 7 = 25
- 2x = 25 - 7
- 2x = 18
- x = 18/2
- x = 9
thus, kwam is 9 years old and ayi is 9 + 7 = 16 years old .
Answer:
Kwame = [tex] 9 [/tex] years old
Ayi = [tex] 16 [/tex] years old
Step-by-step explanation:
Let's denote Kwame's age as [tex] x [/tex] years.
According to the given information, Ayi is [tex] 7 [/tex] years older than Kwame, so Ayi's age is [tex] x + 7 [/tex] years.
The sum of their ages is [tex] 25 [/tex] years, so we can write the equation:
[tex] x + (x + 7) = 25 [/tex]
Now, let's solve for [tex] x [/tex]:
[tex] 2x + 7 = 25 [/tex]
[tex] 2x = 25 - 7 [/tex]
[tex] 2x = 18 [/tex]
[tex] x = \dfrac{18}{2} [/tex]
[tex] x = 9 [/tex]
Now that we know Kwame's age is [tex] 9 [/tex] years, we can find Ayi's age:
[tex] \text{Ayi's age} = x + 7 = 9 + 7 = 16 [/tex]
Therefore, Kwame is [tex] 9 [/tex] years old and Ayi is [tex] 16 [/tex] years old.