Respuesta :

Answer :

  • Ayi = 16 y/o
  • Kwame = 9 y/o

Explanation :

Let the age of kwame be x and that of Ayi be x + 7

ATQ,

  • x + x + 7 = 25
  • 2x + 7 = 25
  • 2x = 25 - 7
  • 2x = 18
  • x = 18/2
  • x = 9

thus, kwam is 9 years old and ayi is 9 + 7 = 16 years old .

msm555

Answer:

Kwame = [tex] 9 [/tex] years old

Ayi = [tex] 16 [/tex] years old

Step-by-step explanation:

Let's denote Kwame's age as [tex] x [/tex] years.

According to the given information, Ayi is [tex] 7 [/tex] years older than Kwame, so Ayi's age is [tex] x + 7 [/tex] years.

The sum of their ages is [tex] 25 [/tex] years, so we can write the equation:

[tex] x + (x + 7) = 25 [/tex]

Now, let's solve for [tex] x [/tex]:

[tex] 2x + 7 = 25 [/tex]

[tex] 2x = 25 - 7 [/tex]

[tex] 2x = 18 [/tex]

[tex] x = \dfrac{18}{2} [/tex]

[tex] x = 9 [/tex]

Now that we know Kwame's age is [tex] 9 [/tex] years, we can find Ayi's age:

[tex] \text{Ayi's age} = x + 7 = 9 + 7 = 16 [/tex]

Therefore, Kwame is [tex] 9 [/tex] years old and Ayi is [tex] 16 [/tex] years old.