Respuesta :

msm555

Answer:

[tex] \sf Area = 64 \, \textsf {in.} ^2[/tex]

Step-by-step explanation:

The area (A) of a parallelogram is given by the formula:

[tex] \Large\boxed{\boxed{\sf Area(A) = \textsf{base} \times \textsf{height} }}[/tex]

In this case base (b) is 8 inches and the height (h) is 8 inches, substitute these values into the formula:

[tex] \sf Area(A) = 8 \times 8 [/tex]

[tex] \sf Area(A) = 64 \, \textsf {in} ^2[/tex]

So, the area of the parallelogram is 64 square inches.

ghxstii

Answer:

64 in.²

Step-by-step explanation:

Since the length and width are both 8 in., we can see that all the measures are equal to each other.

All the angles are 90 degrees, and all the sidelengths are 8 in.

So, since area is length * width, we multiply 8 * 8. We know that is 64, so the area is 64 in.²

I hope this helps :) if so, brainliest would help me out a lot <3

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