What are the zeros of the quadratic function below? f(x)=3x2+11x−4 A. x=−4 and x=−13 B. x=−4 and x=13 C. x=4 and x=−13 D. x=4 and x=13

Respuesta :

Answer:

The correct choice that represents these zeros is not provided in the options.

Step-by-step explanation:

To find the zeros of the quadratic function \( f(x) = 3x^2 + 11x - 4 \), we need to set the function equal to zero and solve for \( x \). The zeros of a function are the values of \( x \) that make the function equal to zero.

1. Set the function equal to zero:

\( 3x^2 + 11x - 4 = 0 \)

2. Factor the quadratic equation or use the quadratic formula to solve for \( x \):

The factored form of the quadratic equation can be written as:

\( (3x - 1)(x + 4) = 0 \)

3. Find the zeros by setting each factor equal to zero:

\( 3x - 1 = 0 \) and \( x + 4 = 0 \)

Solving these equations gives:

\( 3x = 1 \) → \( x = \frac{1}{3} \)

\( x = -4 \)

Therefore, the zeros of the quadratic function \( f(x) = 3x^2 + 11x - 4 \) are \( x = \frac{1}{3} \) and \( x = -4 \). The correct choice that represents these zeros is not provided in the options.