C6H12O6→2C2H5OH+2CO2
This equation tells us that one molecule of glucose (C6H12O6) can produce two molecules of ethanol (C2H5OH).
To find out how much ethanol can be produced from 25g of glucose, we first need to know the molar masses of glucose and ethanol. The molar mass of glucose is approximately 180.16 g/mol and the molar mass of ethanol is approximately 46.07 g/mol.
From the balanced equation, we know that 1 mol of glucose produces 2 mol of ethanol. So, we can set up the following proportion to find out how much ethanol can be produced from 25g of glucose:
1 mol of glucose180.16 g of glucose=x mol of glucose25 g of glucose
Solving for x gives us the number of moles of glucose in 25g. Then, we can use the balanced equation to find out how many moles of ethanol are produced:
2 mol of ethanol1 mol of glucose=y mol of ethanolx mol of glucose
Solving for y gives us the number of moles of ethanol produced. Finally, we can convert this to grams using the molar mass of ethanol:
y mol of ethanol×46.07 g/mol=z g of ethanol
Where z is the mass of ethanol that could be obtained from 25g of glucose.