let x be volume of 5% acid and y be volume of the 8%
x + y = 750 and
0.05x + 0.08y = 0.07*750 = 52.5
from first equation y = 750 - x so substituting in the second equation:-
0.05x + 0.08(750 - x) = 52.5
0.05 - 0.08x = 52.5 - 60
-0.03x = -7.5
x = -7.5 / -0.3 = 250 mls <------ answer