Respuesta :

Angle ABC= Angle B.
He tells you BD bisects angle ABC (B) which means a line passes through the point and splits it into two equal angles= ABD and DBC.
Since ABD=DBC then: 5x=3x+10 
5x-3x=10      2x=10      x=10/2 x=5Since Angle BD bisects angle ABC then Angle ABC equals the two halves ABD and DBC.    substitute x.  ABD=5x=5*5=25  DBC=3x+10=3*5+10=15+10=25  . So ABC = ABD +DBC = 25+25 = 50

An angle bisector is a line segment that divides an angle into two

The measure of angle ∠ABC is 50° (degrees)

The reason for arriving at the above angle measurement is s follows:

The given information are;

The segment BD = The angle bisector of the angle ∠ABC

∠ABD = 5·x

∠DBC = 3·x + 10

Method:

Calculate the vale of x based on the given angular relationships

Solution:

By angle addition postulate, we have;

∠ABD + ∠DBC = ∠ABC

Given that BD bisects angle ∠ABC, (into two equal angles), to give ∠ABD and ∠DBC, we get;

∠ABD = ∠DBC

By substitution property, we get;

5·x = 3·x + 10

Which gives;

5·x - 3·x = 10

2·x = 10

x = 10/2 = 5

x = 5

Therefore, from ∠ABD + ∠DBC = ∠ABC, where, ∠ABD = 5·x, and ∠DBC = 3·x + 10, we get;

∠ABD + ∠DBC = 5·x + 3·x + 10 = 8·x + 10 = ∠ABC

∠ABC = 8·x + 10

Plugging in the value of x into the above equation gives;

∠ABC = 8 × 5 + 10 = 50

Angle ∠ABC  = 50°

Learn more about word problems, simultaneous equations and angle bisectors here:

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