A spherical balloon is inflated so that its volume is increasing at the rate of 3.9 ft3/min. How rapidly is the diameter of the balloon increasing when the diameter is 1.7 feet? The diameter is increasing at

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Answer:To find how rapidly the diameter of the balloon is increasing when the diameter is 1. 7 feet, we can use the formula for the volume of a sphere:.

V = (4/3)πr^3.

where V is the volume and r is the radius of the sphere. Since the diameter is twice the radius, we have:.

d = 2r.

Differentiating both sides with respect to time t, we get:.

dV/dt = 4πr^2(dr/dt).

Given that dV/dt = 3. 9 ft^3/min, and we need to find dr/dt when d = 1. 7 feet, we can substitute these values into the equation to solve for dr/dt.

Step-by-step explanation: