A stock solution has a concentration of 3M ZnCl and is diluted to a 0.6 M solution with a volume of 0.45 L. What was the volume of the stock solution?
A. 0.06 L
B. 0.08 L
C. 0.09 L
D. 0.11 L

Respuesta :

Answer:

To solve this problem, we can use the dilution formula, which states that the initial concentration multiplied by the initial volume equals the final concentration multiplied by the final volume.

Initial concentration * Initial volume = Final concentration * Final volume

Let's denote:

- Initial concentration of the stock solution (3 M) as C1

- Initial volume of the stock solution as V1

- Final concentration after dilution (0.6 M) as C2

- Final volume after dilution (0.45 L) as V2

The equation becomes:

3 M * V1 = 0.6 M * 0.45 L

Now, let's solve for V1 (the volume of the stock solution):

V1 = (0.6 M * 0.45 L) / 3 M

V1 = 0.09 L

So, the volume of the stock solution was 0.09 L.

Therefore, the correct answer is:

C. 0.09 L

Explanation:

please give me the brilliant answer okay bro