Find the value of x with a line going out not on the center with the length of 4 and 12

Answer:
x = 8
Step-by-step explanation:
The diagram shows a tangent x and a secant 4, 12
The square of the tangent is equal to the product of the measures of the secant's external part and the entire secant, that is
x² = 4(4 + 12) = 4 × 16 = 64 ( take square root of both sides )
[tex]\sqrt{x^2}[/tex] = [tex]\sqrt{64}[/tex] , that is
x = 8