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A car travelling with a uniform velocity of 30m/s along a horizontal road overcomes a constant frictional force of 600N. Calculate the power of the engine of the car. 

Respuesta :

MathPhys

Answer:

18 kW

Explanation:

Power = work / time

Work = force × distance

Speed = distance / time

Therefore:

P = W / t

P = Fd / t

P = Fv

Plug in values:

P = (600 N) (30 m/s)

P = 18,000 W

P = 18 kW

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