Answer:
1.79 × 10⁻⁵ mole
Explanation:
We are asked to find the number of moles of lipitor in a 0.0100 g dose, given that the molar mass is 558.63 g/mol.
To do this, we can multiply the mass by the molar mass:
[tex]0.0100\not\!\!\!\text{ g} \times \dfrac{1\text{ mole}}{558.63\not\!\!\!\text{ g}} =\boxed{ 1.79\times 10^{-5}\text{ mole}}[/tex]
Notice that because we need to cancel the gram units, we flip the molar mass ratio. We can do this because it is effectively a 1 : 1 ratio. Since
[tex]1\text{ mole lipitor} = 558.63\text{ g lipitor}[/tex],
we can say that:
[tex]\dfrac{1\text{ mole}}{558.63\text{ g}} =\dfrac{558.63\text{ g}}{1\text{ mole}} = 1[/tex]
