Answer:
200 N/m
100 J
Explanation:
Hooke's law states that the force to stretch a spring is equal to the spring constant times the displacement.
F = kx
200 N = k (1.00 m)
k = 200 N/m
The elastic energy stored in a spring is:
EE = ½ kx²
EE = ½ (200 N/m) (1.00 m)²
EE = 100 J