Water decomposes to produce hydrogen and oxygen.
Balanced equation:
2H₂O -> 2H2 + O2
b. If 36.0 grams of water are decomposed, what is the theoretical yield of H₂ (g)?
c. If 36.0 grams of water are decomposed, what is the theoretical yield of O2 (g)?

Respuesta :

If you are dealing wiyh the decomposition of hydrogen peroxide , the equation is :

2H2O2 → 2H2O + O2

2 mol hydrogen peroxide decomposes to produce 2 mol H2O and 1 mol O2

no hydrogen gas is produced .

The only data that I can interpret is that “ 32.0 g gas is produced” I have interpreted this to mean that 32.0 g oxygen O2 gas are produced. This is exactly 1 mol O2 .

So you can say :

When 2 mol hydrogen peroxide decompose 2 mol water and 1 mol O2 gas are produced

And if you want this as a mass:

Molar mass H2O2 = 34 g/mol

Molar mass H2O = 18 g/mol

Molar mass O2 = 32 g/mol

In mass units

When 68 g H2O2 decompose , 36 g H2O and 32 g O2 are produced.