Answer:
\(2y+2y-5y+y-5-10-515\)AlgebraTrigonometryCalculus1 of 3⬚⬚⬚⬚√<()AC⬚⬚|⬚|≤789÷log⬚⬚!>456×i%≥123−xy=0.+2 of 3sincostan()ACcscseccot789÷arcsinarccosarctan456×⬚2⬚°π123−xy=0.+3 of 3⬚∞⬚⬚√()AClim⬚→⬚lim⬚→⬚+lim⬚→⬚−789÷log⬚(,)(,)456×Σ∫⬚∫⬚⬚⬚123−xye0.+ Simplify 1Add the numbers\(2y+2y-5y+y\textcolor{#C58AF9}{-5}\textcolor{#C58AF9}{-10}\textcolor{#C58AF9}{-515}\)\(2y+2y-5y+y\textcolor{#C58AF9}{-530}\)2Combine like terms\(\textcolor{#C58AF9}{2y}+\textcolor{#C58AF9}{2y}\textcolor{#C58AF9}{-5y}+\textcolor{#C58AF9}{y}-530\)\(-530\) Solution \(-530\)
