How much 0.05M HCI solution can be made by diluting 250mL of 10M HCL? (record the answer in mL, do NOT type the
UNITS)
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Respuesta :

To calculate how much 0.05M HCl solution can be made by diluting 250mL of 10M HCl solution, we can use the formula for dilution: \( C1V1 = C2V2 \) Where: - \( C1 \) = initial concentration of the solution (10M) - \( V1 \) = volume of the initial solution (250mL) - \( C2 \) = final concentration of the solution (0.05M) - \( V2 \) = volume of the final solution to be calculated By substituting the values into the formula, we get: \( 10M \times 250mL = 0.05M \times V2 \) Solving for \( V2 \): \( 10M \times 250mL = 0.05M \times V2 \) \( 2500 = 0.05V2 \) \( V2 = 2500 / 0.05 \) \( V2 = 50000 mL \) Therefore, you can make 50000mL (or 500mL) of 0.05M HCl solution by diluting 250mL of 10M HCl solution.